Group Selfies

The lads and I working and reviewing some crash course.

The lads and I watching a few bozeman science videos.

Jazlyn and I organizing our 100% completed notebooks.

H-Weezy Problem

Solving A Hardy-Weinberg Equation

Step 1- Find given components, in this case they were q² and the population size.

→q²= .48 and population is 1000

Step 2- In order to find q you must square root it. Then once acquired q you simply subtract q to 1 then that will give you your p value.

→√q²=√.48 → q= .69

→ .69 - 1 = .31 → p=.31

Step 3- Next is to get p², to do this you just square your p value. After getting your p and q values you plug them into 2pq to get that value.

→ p= .31 → .3² = .09 → p²= .09

→ 2pq → 2(.31)(.69) = .43

Step 4- To ensure your calculations are correct you take the Hardy-Weinberg equation and plug the values in. They should equal a total of 1.

→ p²+2pq+q²=1

→ .09 + .43 + .48 = 1

Homozygous dominant individual- p²: .09                                           

Homozygous recessive individual- q²: .48             

Frequency of dominant allele- p : .31               

Frequency of recessive allele- q : .69              

Heterozygous individual- 2pq: .43

Step 5- By multiplying your p², q², and 2pq individually by the population size, you then get your possible genotypes.

→ .09 × 1000 = 90

→ .48 × 1000 = 480

→ .43 × 1000 = 430

Step 6- Finally to get the frequencies of the alleles you simply turn them into percentages.

Frequency of Dominant Allele→ p = .31 → 31%

Frequency of Recessive Allele→ q = .69 → 69%

California Blackworm Data

       

Data	Diana	Eric	Sylvia	Ivana	Sarah	Jessica	Angela	Claudia	Anna	Results
A 1 2 3 4 5	D 1  D 2 28  31 27  42 30  32 23  30 25  39 Avg.30.7	D 1  D 2 43  41 49  47 49  43 35  39 21  35 Avg.40.2	D 1  D 2 30  33 35  26 49  34 44  37 46  35 Avg.36.9	D 1  D 2 00  28 00  28 00  31 00  33 00  27 Avg.24.4	D 1  D 2 42  42 33  43 38  30 40  27 37  40 Avg.37.2	D 1  D 2 10  7 13  20 13  20 5   15 6   16 Avg.12.6	D 1  D 2 00  16 00  18 00  19 00  16 00  12 Avg.16.2	D 1  D 2 00  48 00  28 00  41 00  39 00  30 Avg.37.2	D 1  D 2 45  40 34  36 30  30 39  41 38  45 Avg.37.8	=273.4 Avg. Total Depressant
B 1 2 3 4 5	D 1  D 2 20  22 26  40 29  43 25  40 26  41 Avg.31.2	D 1  D 2 26  28 35  22 34  30 31  24 28  28 Avg.28.6	D 1  D 2 00  34 00  30 00  35 00  33 00  32 Avg.32.8	D 1  D 2 00  33 00  38 00  34 00  37 00  33 Avg.35	D 1  D 2 29  42 26  25 25  28 31  29 29  31 Avg.29.5	D 1  D 2 12  4 29  7 17  11 15  13 16  26 Avg.15	D 1  D 2 00  18 00  35 00  28 00  30 00  29 Avg.25	D 1  D 2 00  44 00  48 00  72 00  60 00  40 Avg.52.8	D 1  D 2 40  42 40  35 49  40 40  40 40  36 Avg.40.2	=293.1 Avg. Total Water/Neutral
C 1 2 3 4 5	D 1  D 2 20  30 16  35 21  40 21  37 14  34 Avg.26.8	D 1  D 2 32  38 39  26 43  31 37  24 34  40 Avg.34.4	D 1  D 2 00  44 00  37 00  39 00  46 00 54 Avg.44	D 1  D 2 00  35 00  24 00  31 00  29 00  32 Avg.30.8	D 1  D 2 28  31 43  22 40  23 41  45 45 41 Avg.35.9	D 1  D 2 14  18 17  16 14  15 15  23 19  20 Avg.17.1	D 1  D 2 00  18 00  25 00  25 00  20 00  19 Avg.21.4	D 1  D 2 00  48 00  28 00  41 00  39 00  30 Avg.37.2	D 1  D 2 45  50 39  41 41  36 44  50 55  52 Avg.45.3	=328.9 Avg. Total Stimulant

           Using the data collected in class, I analyzed each groups pulse counts and determined how I would encode which was the depressant, the stimulant, and then the normal water. I first added up each groups data both day 1 and day 2, which I then calculated their average. My reasoning behind doing this would allow me to discover each groups combined data to then add each column A, B, and C. Adding all groups averages then allowed me to discover each substances normal average within the class and also enable which seemed to be the depressant, stimulant, and the normal water. My discovery was that substance A was the depressant due to having a total of 273.2 for both days. Substance B from my findings was the normal water the worms were in due to having a total of 293.1 and finally the C substance consisted of the stimulant which I calculated to obtain the total of 328.7 for both days.