Solving A Hardy-Weinberg Equation
Step 1- Find given components, in this case they were q² and the population size.
→q²= .48 and population is 1000
Step 2- In order to find q you must square root it. Then once acquired q you simply subtract q to 1 then that will give you your p value.
→√q²=√.48 → q= .69
→ .69 - 1 = .31 → p=.31
Step 3- Next is to get p², to do this you just square your p value. After getting your p and q values you plug them into 2pq to get that value.
→ p= .31 → .3² = .09 → p²= .09
→ 2pq → 2(.31)(.69) = .43
Step 4- To ensure your calculations are correct you take the Hardy-Weinberg equation and plug the values in. They should equal a total of 1.
→ p²+2pq+q²=1
→ .09 + .43 + .48 = 1
Homozygous dominant individual- p²: .09
Homozygous recessive individual- q²: .48
Frequency of dominant allele- p : .31
Frequency of recessive allele- q : .69
Heterozygous individual- 2pq: .43
Step 5- By multiplying your p², q², and 2pq individually by the population size, you then get your possible genotypes.
→ .09 × 1000 = 90
→ .48 × 1000 = 480
→ .43 × 1000 = 430
Step 6- Finally to get the frequencies of the alleles you simply turn them into percentages.
Frequency of Dominant Allele→ p = .31 → 31%
Frequency of Recessive Allele→ q = .69 → 69%
